Is there a mistake in my homework question?

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Oxidation involves the loss of electrons, resulting in a decrease in negative charge, while reduction is the opposite. In the provided question regarding oxidation reactions, participants express confusion over identifying which reactions represent oxidation or reduction. The discussion emphasizes the importance of balancing reactions and understanding oxidation numbers. Assigning oxidation numbers to manganese (Mn) in various compounds is crucial for determining whether electrons are gained or lost. The oxidation number for oxygen remains consistently -2, which helps clarify the electron transfer for Mn. By analyzing the changes in oxidation states, one can correctly identify the oxidation reactions among the options given. The principle of "OIL RIG" (Oxidation Is Loss, Reduction Is Gain) is highlighted as a helpful mnemonic for understanding these processes.
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Hey guys. I know that oxidation is a atom/molecule/ion losing electrons, therefor whenever that happens the minus decreases until it may become a plus.

Reduction is just the opposite.

But in the following question there are 3 options for oxidation reaction and 1 for reduction! And I can only pick 1 answer. I'm confused, and not sure what to do. Any help?

The question:

Which of the following is an oxidation reaction?

MnO2 >>>>> Mn2+
MnO42- >>>>> MnO2
MnO2 >>>>> MnO4-
MnO4- >>>>> MnO2
 
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Hi,
I guess you need to consider balancing of reactions. Maybe you have to check which equation is balanced and choose the oxidation reaction from them.
I maybe wrong but i don't have any clue!
 
Dory said:
Hey guys. I know that oxidation is a atom/molecule/ion losing electrons, therefor whenever that happens the minus decreases until it may become a plus.

That would work when comparing oxidation state of two otherwise identical ions (that is, differing only by charge). When composition changes, it is no longer correct.

Do you know what oxidation numbers are? Try to assign them to Mn in all compounds. Where does the ON go up?
 
Sorry, I'm having tough time. I know what oxidation numbers are... this question is just befuddling me. I still see 1 reduction and 3 oxidations... sigh
 
List all oxidation numbers, for all substances.
 
(Sorry it takes me a while to reply...am a busy woman)

Oxidation Numbers:

Mn+4 O-4 >>> Mn+2
Mn+6 O-8 >>> Mn+4 O-4
Mn+4 O-4 >>> Mn+3 O-4
Mn+3 O4 >>> Mn+4 O-4

I'm not sure what are they supposed to tell me with respect to the answer. Looking at the reactions as is and determining whether they're oxidation or reduction based on what we we know (OIL RIG - Oxidation Is Loss of e-, Reduction is Gain of e-) makes more sense to me.
 
You are wrong when it comes to oxidation number of oxygen - it is per atom, not per all atoms, so in each case ON for oxygen is -2. But you have correctly calculated sums, so it shouldn't matter much. However, there is a problem with ONs for Mn in different compounds:

Dory said:
Mn+4 O-4 >>> Mn+2

OK

Mn+6 O-8 >>> Mn+4 O-4

OK

Mn+4 O-4 >>> Mn+3 O-4

OK for MnO2, but wrong for MnO4- - 4 oxygens at -2 mean -8, not -4.

Mn+3 O4 >>> Mn+4 O-4

Same problem.

I'm not sure what are they supposed to tell me with respect to the answer. Looking at the reactions as is and determining whether they're oxidation or reduction based on what we we know (OIL RIG - Oxidation Is Loss of e-, Reduction is Gain of e-) makes more sense to me.

Same approach will help. Even if you don't see all oxygens in the not fully balanced reaction as those presented, you can safely assume ON for oxygen doesn't change - it is always -2. That means oxygen neither gains nor losses electrons, so any change that happens must be either electron gain or loss for Mn. Knowing oxidation numbers for Mn before and after reaction you can tell whether it gained or lost electrons, then OIL RIG will give you answer you are looking for.

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