Is there a standard equation for a 4 by 4 inverse?

HF08
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Inquiry:

Is there a standard equation for a 4 by 4 inverse? I know that one exists for 3 by 3, 2 by 2, but I cannot find one in my text nor in my searches online. I know I could find one by using the Jordan-Gaussian Method. But, I would be more comfortable with knowing a 4 by 4 general method/equation. I plan on doing a lot of inverses for a 4 by 4.

If you know of any resources, please help me. Also, if I should find this on my own by scratch, please help me.

Thank You,
HF08
 
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Yes, you should probably create an explicit formula on your own. You don't find it listed just because it's lengthy to write down. But it should be an obvious extension of the lower dimensional cases. It's a matrix of the determinants of the minors of the nxn matrix divided by the determinant of the whole matrix.
 
Thanks

Dick said:
Yes, you should probably create an explicit formula on your own. You don't find it listed just because it's lengthy to write down. But it should be an obvious extension of the lower dimensional cases. It's a matrix of the determinants of the minors of the nxn matrix divided by the determinant of the whole matrix.


Can you please provide some links to the n = 2 and n = 3 cases please? After that, I'll do the rest on my own. Thanks.

HFO8
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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