Is This a Conservation of Momentum Problem?

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The discussion revolves around a physics problem involving a projectile and a wooden block, focusing on the conservation of momentum principle. The initial momentum of the system must equal the final momentum after the projectile passes through the block. A participant incorrectly applied an equation for the scenario, prompting another to suggest consulting a textbook section on collisions for the correct approach. The key takeaway is to set the initial momentum equal to the final momentum to solve for the projectile's exit velocity. This problem exemplifies the application of conservation laws in physics.
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A 0.165 kg projectile is fired with a velocity of +705 m/s at a 2.00 kg wooden block that rests on a frictionless table. The velocity of the block, immediately after the projectile passes through it, is +55.0 m/s. Find the velocity with which the projectile exits from the block.

I am having trouble solving this problem. I used this equation:
vf1=(0.165-2.00)/(0.165+2.00)*705, but the answer is wrong. Am I using the right equation?
 
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LOL, we could quite possibly be in the same class. Again, yet another homework problem that I had.

I can tell you that no, that isn't the correct equation to be using. Look in your book under 7.4 : Collisions in Two Dimensions and you will get the correct equation to use from there.
 
this question seems as if it is a conservation of momentum problem.
therefore,
initial momentum (before collison) must be equal to the
final momentum (after collison)

so just equate the two and you should get the correct answer.

hope this helps.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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