Is this a trick question? more springs

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The discussion revolves around a physics problem involving a block propelled by a spring on a frictionless incline. Participants clarify that the block starts at rest and gains velocity once the spring uncompresses. The key equation for maximum height reached by the block is identified as (1/2)kx_0^2 = mgh, focusing on energy conservation. There is debate about the necessity of the incline angle, with some suggesting it may not be needed if only vertical height is considered. The conversation raises the possibility that the problem may expect a different interpretation regarding height measurement along the slope versus vertical height gain.
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Homework Statement



A block with mass m is held against a compressed spring and then the spring is allowed to uncompress giving the block a velocity. The block slides to the right and then up an incline. Find the maximum height that the block reaches if the incline is \theta degrees. All surfaces are frictionless, the spring constant is k and the initial spring compression is x_0.


The Attempt at a Solution



It says it gives the block a certain velocity, but that is after it releases right? So initally it still at rest. Also is the angle really necessary?

So really is it just

\frac{1}{2}kx_0 ^2 = mgh
 
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flyingpig said:

Homework Statement



A block with mass m is held against a compressed spring and then the spring is allowed to uncompress giving the block a velocity. The block slides to the right and then up an incline. Find the maximum height that the block reaches if the incline is \theta degrees. All surfaces are frictionless, the spring constant is k and the initial spring compression is x_0.


The Attempt at a Solution



It says it gives the block a certain velocity, but that is after it releases right? So initally it still at rest. Also is the angle really necessary?

So really is it just

\frac{1}{2}kx_0 ^2 = mgh

You are right about the velocity.
With regard to height, I would agree you don't need the angle if you are considering vertical height gain, which makes me wonder if they are expecting an answer like x metres up the slope, rather than a vertical height gain??
 
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