CraigH
- 221
- 1
Mistake 1.
In the lecture slides from my university it says that:
"The response of a stable first-order transfer function to a unit sine wave input is:"
Y(s)=\frac{1}{s+a}*\frac{\omega}{s^2+\omega^2}
Isn't this missing an a in the numerator since the standard form of a first order transfer function is:
H(s) = \frac{1}{\tau s +1} = \frac{a}{s+a}
where \tau=1/a
and the laplace transform of the sine wave input is:
\frac{\omega}{s^2+\omega^2}
Mistake 2.
The lecture slides also say that:
"The response of a stable second-order transfer function to a unit sine wave input is:"
Y(s)=\frac{1}{s^2+2\zeta\omega_n+\omega_n^2}*\frac{\omega}{s^2+\omega^2}
Similarly, isn't this missing an \omega_n^2 in the numerator as the standard form of a second order transfer function is:
H(s) = \frac{\omega_n^2}{s^2+2 \zeta \omega_n s + \omega_n^2}
In the lecture slides from my university it says that:
"The response of a stable first-order transfer function to a unit sine wave input is:"
Y(s)=\frac{1}{s+a}*\frac{\omega}{s^2+\omega^2}
Isn't this missing an a in the numerator since the standard form of a first order transfer function is:
H(s) = \frac{1}{\tau s +1} = \frac{a}{s+a}
where \tau=1/a
and the laplace transform of the sine wave input is:
\frac{\omega}{s^2+\omega^2}
Mistake 2.
The lecture slides also say that:
"The response of a stable second-order transfer function to a unit sine wave input is:"
Y(s)=\frac{1}{s^2+2\zeta\omega_n+\omega_n^2}*\frac{\omega}{s^2+\omega^2}
Similarly, isn't this missing an \omega_n^2 in the numerator as the standard form of a second order transfer function is:
H(s) = \frac{\omega_n^2}{s^2+2 \zeta \omega_n s + \omega_n^2}
Last edited: