Is total flux linkage λ=dΨ*Ienclosed/I or λ=N*Ψ?

In summary, in the conversation, the formula dλ=dΨ * Ienclosed/I was discussed for determining total flux linkage in a coaxial cable for ρ<a and a<ρ<b. However, when applied to a solenoid, this formula did not work and instead, the formula λ=N*Ψ was found to be effective. The question of why Ienclosed/I is multiplied in the coaxial cable was also raised, but without further context or definition of symbols, the purpose of this calculation is unclear.
  • #1
ElieMakdissi
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TL;DR Summary
I don't understand why we multiply by Ienclosed/I the total flux linkage
In Sadiku, he used the formula dλ=dΨ * Ienclosed/I
to determine the total flux linkage for coaxial cable for ρ<a and for a<ρ<b, but I applied this formula for the solenoid and it didn't work, the way that works for the solenoid is by using λ=N*Ψ.

So why we multiply by Ienclosed/I in the coaxial cable?
 
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  • #2
Without context and even a definition of your symbols I have no clue what you are talking about. E.g., are you looking at the coax cable from the point of view of the "telegrapher's equation", which is a quasistationary approximation, or the full wave-guide theory a la Maxwell and Hertz? What's ##\Psi##?
 
  • #3
IMG_20230527_160545.jpg
 

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