Is Vo Independent of Rs in Non-Inverting Op-Amps?

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The discussion centers on the independence of output voltage (vo) from source resistance (Rs) in non-inverting op-amps. The user initially struggles with the concept and equations, particularly regarding the role of input resistances. After some exploration, they successfully determine the voltage at the positive input (vp) and calculate the output voltage using the correct circuit configuration. The final output voltage is found to be 9000 mV, indicating a successful resolution of the problem. The user expresses satisfaction with their understanding and solution.
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Homework Statement



npi9za.png



Homework Equations



vo = G*vs

where G = ((R1+R2)/(R2)

therefore,
vo = vs * ((R1+R2)/(R2)

would vo be independent of Rs ?

The Attempt at a Solution



I assumed it was a Non Inverting Op Amp...but I haven't come across one with (two?) input resistances? I'm not sure where to go with it. I began to use the equation I have above, but I don't think it's right. I think (or I keep telling myself) that I have to use Rs or Rx in part a somehow.

For part b) I believe I have to figure out the linear range of Rx, which should be doable. So I'm not worried about that, assuming what I'm thinking is correct...

If anyone can help thanks! If not, thanks anyways!
 
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One question that may help - What is the voltage at the + input of the Op Amp. Is it 750 mV, or something else?
 
Inept said:

Homework Statement



npi9za.png

Homework Equations



vo = G*vs

where G = ((R1+R2)/(R2)

therefore,
vo = vs * ((R1+R2)/(R2)

would vo be independent of Rs ?

The Attempt at a Solution



I assumed it was a Non Inverting Op Amp...but I haven't come across one with (two?) input resistances? I'm not sure where to go with it. I began to use the equation I have above, but I don't think it's right. I think (or I keep telling myself) that I have to use Rs or Rx in part a somehow.

For part b) I believe I have to figure out the linear range of Rx, which should be doable. So I'm not worried about that, assuming what I'm thinking is correct...

If anyone can help thanks! If not, thanks anyways!

For starters, what is the voltage at the + input (in terms of Vs)?

EDIT: phyzguy had the same thought.
 
I solved it, I had to solve for a non-inverting (positive) input voltage (vp) first and then created a "new" circuit. Using that circuit I found the output voltage using that equation I listed above while replacing vs with vp . I got vp = [(80k/(80k+20k)]*750 mV = 600 mV

then vo = [(3.3k+46.2k)/3.3k]*600 mV = 9000 mVIt feels good to figure my own answer out...lolEDIT: I didnt refresh, so I didn't see your guys replies. Thanks all! :)
 
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