Jackson Problem 3.12/3.18 -- Electric potential near two plates

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SUMMARY

The discussion focuses on solving the electric potential problem as outlined in Jackson's textbook, specifically problems 3.12 and 3.18. The configuration involves two plates, with one plate at Z=0 having a potential V and the other grounded. The solution to problem 3.12 provides a partial answer using Bessel functions, but additional steps are necessary to fully address the boundary conditions for problem 3.18. Utilizing the Green function and applying equation 1.44 is essential for determining the potential in the volume.

PREREQUISITES
  • Understanding of electrostatics and electric potential
  • Familiarity with Bessel functions and their applications
  • Knowledge of Green's functions in solving differential equations
  • Proficiency in applying boundary conditions in electrostatic problems
NEXT STEPS
  • Study the application of Green's functions in electrostatics
  • Review Jackson's problem 3.17 for insights on boundary conditions
  • Learn about Bessel function solutions in cylindrical coordinates
  • Examine the implications of equation 1.44 in electrostatic potential calculations
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Students and professionals in physics, particularly those focusing on electrostatics, as well as anyone tackling advanced problems in potential theory and boundary value problems.

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Homework Statement


I need to solve a problem like Jackson 3.18. I need to find potential due to the same configuration but the position of two plates is opposite i.e. Plate at Z=0 contains disc with potential V and plate at Z=0 is grounded.

Homework Equations

The Attempt at a Solution


I think solution of problem 3.12 gives half of the solution as the value of potential in terms of bessel solution. But, i can't figure out what additional things must be done to complete this problem in addition to problem 3.12.
 

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Hello, and welcome to PF!

You need to reconsider the function Z(z). The boundary condition for this function changes when going from prob. 3.12 to prob. 3.18.
 
This is a straightforward application of the result of problem 3.17, once you have the Green function, then simple application of equation 1.44 gives you the potential in the volume.
 

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