Jacobian transformation, find new limits

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 2K views
Feodalherren
Messages
604
Reaction score
6

Homework Statement


jacobian.png



Homework Equations





The Attempt at a Solution


What I don't understand is how I'm supposed to find those limits for U and V. That's not at all what I'm getting. I've tried solving for the max and min x,y coordinates from the given graphs but that doesn't yield the correct answer.
 
Physics news on Phys.org
Look at the original equations you are given:

##x - 2y = 0##
##x - 2y = 4##
##3x - y = 1##
##3x - y = 8##

Applying your transformation yields:

##u = 0##
##u = 4##
##v = 1##
##v = 8##

These yield your limits.
 
  • Like
Likes   Reactions: 1 person
Feodalherren said:
What I don't understand is how I'm supposed to find those limits for U and V. That's not at all what I'm getting. I've tried solving for the max and min x,y coordinates from the given graphs but that doesn't yield the correct answer.
It unfortunate that you did not tell us how you tried "solving for the max and min x, y coordinates" since if you had we might be able to point out your mistake. All I can say is that if you have "u= x- 2y", one of the boundaries is x- 2y= 0 and the other is x- 2y= 4, u= 0 and 4 pretty much leaps out at you- u= x- 2y= 0 and u= x- 2y= 4!