Jet Pilot Loop: Solve 2 Physics Problems in 1 Hour

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In summary, a jet pilot is performing a vertical loop at a speed of 1300 km/h. To ensure the safety of the pilot, the minimum radius of the circle must be determined so that the centripetal acceleration at the lowest point does not exceed 6.7 g's. To solve this, the centripetal force formula must be used and the speed must be converted into m/s. For part (b), the pilot's effective weight must be calculated at the bottom and top of the loop, assuming the same speed.
  • #1
RileyAllen
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A jet pilot takes his aircraft in a vertical loop

a. If the jet is moving at a speed of 1300 km/h at the lowest point of the loop, determine the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.7 g's.

b. Calculate the 75-{\rm kg} pilot's effective weight (the force with which the seat pushes up on him) at the bottom of the circle, and at the top of the circle (assume the same speed).


I need much help! This is one of only 2 problems I can not figure out. Due in one hour.
 
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  • #2
For part (a), you must use the centripetal force formula
F = m*(v^2)/r
Replace F with ma.
Convert your speed into m/s.
 
  • #3


I understand the urgency of solving problems within a given time frame. I will do my best to guide you through the problem and provide a solution within the given time limit.

a. To solve this problem, we need to use the equation for centripetal acceleration, which is a = v^2/r, where a is the centripetal acceleration, v is the velocity, and r is the radius of the circle. We also know that 6.7 g's is equivalent to 65.7 m/s^2. Therefore, we can set up the equation as follows:

65.7 m/s^2 = (1300 km/h)^2/r

To solve for r, we need to convert the velocity from km/h to m/s and square it. The conversion factor for km/h to m/s is 1 km/h = 0.2778 m/s. Therefore, the equation becomes:

65.7 m/s^2 = (1300 km/h * 0.2778 m/s)^2/r

Solving for r, we get a minimum radius of 153.3 meters.

b. To calculate the pilot's effective weight, we need to use the equation W = mg, where W is the weight, m is the mass, and g is the acceleration due to gravity. We also know that the pilot's mass is 75 kg and the acceleration due to gravity is 9.8 m/s^2. Therefore, we can set up the equation as follows:

W = 75 kg * 9.8 m/s^2

This gives us a weight of 735 N at both the bottom and top of the circle.

I hope this helps you solve the problems within the given time frame. Remember to always double check your calculations and units to ensure accuracy. Good luck!
 

Related to Jet Pilot Loop: Solve 2 Physics Problems in 1 Hour

1. What is the purpose of the "Jet Pilot Loop: Solve 2 Physics Problems in 1 Hour"?

The purpose of the "Jet Pilot Loop" is to provide a challenging and engaging activity for students to apply their knowledge of physics concepts in a real-world scenario. By solving two physics problems within a limited time frame, students will be able to test their problem-solving skills and deepen their understanding of the subject.

2. Who can participate in the "Jet Pilot Loop"?

The "Jet Pilot Loop" is designed for high school or college students who have a basic understanding of physics principles. However, anyone with an interest in physics can participate and attempt to solve the problems.

3. How difficult are the physics problems in the "Jet Pilot Loop"?

The problems in the "Jet Pilot Loop" are designed to be challenging but not impossible. They require a good understanding of physics concepts and the ability to apply them in a practical scenario. However, with careful thinking and problem-solving skills, participants should be able to successfully solve the problems within the given time frame.

4. Can the "Jet Pilot Loop" be completed alone or in a group?

The "Jet Pilot Loop" can be completed either alone or in a group. However, it is recommended to work in a group as it allows for collaboration and sharing of ideas, which can lead to a more efficient and accurate solution.

5. What should participants expect to gain from completing the "Jet Pilot Loop"?

By completing the "Jet Pilot Loop", participants will gain a deeper understanding of physics concepts and how to apply them in a real-world scenario. They will also improve their problem-solving and critical thinking skills, as well as their ability to work under pressure and within a time limit.

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