What is the force exerted by an oak tree on a jogging person after collision?

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The discussion calculates the force exerted by an oak tree on a jogging person after a collision. A jogger with a mass of 81.9 kg collides with the tree at a speed of 4.7 m/s and rebounds at 4.2 m/s. The change in momentum is determined using the jogger's mass and velocities before and after the collision. By applying the impulse-momentum theorem and Newton's second law, the force exerted by the tree is calculated to be approximately 1584.59 Newtons. This analysis highlights the application of basic physics principles in understanding collision forces.
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If a healthy but somewhat direction impaired individual (mass = 81.9 kg) is jogging through the woods and runs straight into a large oak tree at 4.7 m/s. Rebound speed is measured at 4.2 m/s in the opposite direction. If the time of contact with the tree is 46 milliseconds, what is the magnitude of the force that the tree exerts on the jogger?
 
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What have you done? I suggest applying the acceleration definition (a = \frac{\Delta v}{\Delta t}) directly into Newton's 2nd Law.
 
This is a simple application of an impulse. I = Force * time, and is also the change in momentum. Momentum is mass times velocity. Momentum before = 81.9 * 4.7 = 384.93. Momentum after=81.9*-4.2= -343.98. Impulse = 728.91 = force * time. Time=.46. 728.91=force * .46. Force is then equal to 1584.59 Newtons.
 
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