Juggler throws 2 balls - when do they pass

  • Thread starter Thread starter Rbraind
  • Start date Start date
  • Tags Tags
    Balls
AI Thread Summary
A juggler throws two balls, each at 10 m/s, with the first reaching a height of 2.4 m in 0.24 seconds. The second ball is thrown as the first reaches the ceiling. To determine when the two balls pass, it is established that the time after the second ball is thrown is 0.12 seconds. This is calculated using the equation 20x = 2.4 m, where x represents the time after the second ball is thrown. The solution effectively demonstrates the timing of the balls' paths in relation to each other.
Rbraind
Messages
10
Reaction score
0

Homework Statement



A juggler throws a ball at 10m/s and it takes 0.24 seconds to reach the ceiling which is 2.4m high. As this ball reaches the ceiling he throws a second ball also at 10m/s. How long after 2nd ball is thrown do they pass

Homework Equations


maybe just too late but I am drawing complete blank. I just worked out the time and velocity of the ball and know the same formulas apply- just how, where do i start?


The Attempt at a Solution

?
 
Physics news on Phys.org
Hi Rbraind! :wink:

Do y and t equations for each ball.

You need to find where y and t for one are the same as for the other …

what do you get? :smile:​
 
Rbraind said:

Homework Statement



A juggler throws a ball at 10m/s and it takes 0.24 seconds to reach the ceiling which is 2.4m high. As this ball reaches the ceiling he throws a second ball also at 10m/s. How long after 2nd ball is thrown do they pass

Homework Equations


maybe just too late but I am drawing complete blank. I just worked out the time and velocity of the ball and know the same formulas apply- just how, where do i start?


The Attempt at a Solution

?

I don't think u need an equation for this.
Let x be the time after the 2nd ball has passed
Assume that g=10ms^-1
10x + 10x = 2.4m
20x = 2.4m
x = 0.12 second
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

How long after the second ball is thrown do the two balls pass each other?
Replies
2
Views
6K
Ball on a string thrown around a spool
Replies
3
Views
879
Solving a Ball Thrown off a Cliff: How Long Does it Take?
Replies
4
Views
2K
How Fast Must a Juggler Throw Four Balls?
Replies
1
Views
3K
Calculating Passing Height of Two Thrown Balls
Replies
1
Views
1K
Kinematics: Ball thrown off of a building
Replies
7
Views
2K
Projectile motion: Two Balls and Building
Replies
9
Views
2K
Free Fall Experiment: Predicting Ball's Maximum Height and Time
Replies
4
Views
1K
Finding initial velocity in free fall with given meters.
Replies
3
Views
4K
Ball thrown vertically, only the time is given
Replies
7
Views
3K

Hot Threads

Recent Insights

Back
Top