Why is the Junction Rule not applying in my circuit?

AI Thread Summary
The Junction Rule appears not to apply in the user's circuit due to discrepancies in measured current values, where I1 does not equal the sum of I2 and I3. The discussion highlights potential issues with measurement techniques, including the use of multiple digital voltmeters (DVMs) and their internal shunt resistance affecting readings. Participants suggest verifying the stability of the power supply voltage, as fluctuations could lead to inaccurate measurements. The user is encouraged to clarify their measurement setup and respond to questions regarding resistor values and test procedures. Accurate measurements and a thorough understanding of the circuit setup are essential for resolving the observed charge conservation issue.
vetgirl1990
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Homework Statement


In my lab today, I created a circuit with resistor (R1) in series with a set of resistors in parallel (R2//R3).

Using an ammeter, I measured:
I1 = 2.30mA
I2 = 1.25mA
I3 = 0.38mA

Homework Equations


Junction Rule: ΣI = 0

The Attempt at a Solution


So applying the Junction Rule, I1 = I2 + I3
However, with what I've measured, 12+13 does not add up to I1. What could cause this "loss" of charge? To me, this doesn't make sense, as this violates the idea of conservation of charge. How can charge just disappear like such, after the parallel connection converges?
 

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vetgirl1990 said:

Homework Statement


In my lab today, I created a circuit with resistor (R1) in series with a set of resistors in parallel (R2//R3).

Using an ammeter, I measured:
I1 = 2.30mA
I2 = 1.25mA
I3 = 0.38mA

Homework Equations


Junction Rule: ΣI = 0

The Attempt at a Solution


So applying the Junction Rule, I1 = I2 + I3
However, with what I've measured, 12+13 does not add up to I1. What could cause this "loss" of charge? To me, this doesn't make sense, as this violates the idea of conservation of charge. How can charge just disappear like such, after the parallel connection converges?
Can you show your setup? Remember that a DVM in current measuring mode has an internal shunt resistance that cannot always be ignored...
 
berkeman said:
Can you show your setup? Remember that a DVM in current measuring mode has an internal shunt resistance that cannot always be ignored...
I have just added an image of my set-up in the original post.
 
vetgirl1990 said:
I have just added an image of my set-up in the original post.
Did you really have 6 DVMs running at the same time doing simultaneous monitoring? Or did you have one DVM in voltage mode and one DVM in current mode that you were moving around? What was the actual test procedure? :smile:
 
This might be relevant: http://www.allaboutcircuits.com/textbook/direct-current/chpt-8/voltmeter-impact-measured-circuit/
 
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It would be of interest to know the component values (so that we can compare your measured values to theoretical ones). What were the values of the resistors?
 
berkeman said:
Did you really have 6 DVMs running at the same time doing simultaneous monitoring? Or did you have one DVM in voltage mode and one DVM in current mode that you were moving around? What was the actual test procedure? :smile:
Also, do you see a difference in how you measured the voltage across R1 versus how you handled R2 and R3? :smile:
 
You used a 2 volt supply...so the resistors were around 50 to 150 ohms.

One thing that might or might not be relevant here, but cheap power supplies can drift with time. So it's possible that what started off as 2.0 volts may have been a different value by the time you took your final current measurement. It is a wise precaution to constantly monitor voltage sources if you are not assured of their stability; an unnoticed drift in supply voltage can result in hours of wasted time, and needless frustration!
 
berkeman said:
Did you really have 6 DVMs running at the same time doing simultaneous monitoring? Or did you have one DVM in voltage mode and one DVM in current mode that you were moving around? What was the actual test procedure? :smile:

Exactly to the latter procedure -- I measured each resistor's current and voltage individually. How would that affect the current though?
 
  • #10
vetgirl1990 said:
I measured each resistor's current and voltage individually
Did the voltages add up to 2V?
 
  • #11
vetgirl1990 said:
Exactly to the latter procedure -- I measured each resistor's current and voltage individually. How would that affect the current though?
Can you respond to the other comments and questions in this thread? You have been given some great hints and advice... :smile:
 
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