Just had a Test and I could not get this one

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Two sinusoidal waves create a standing wave, with the distance between the 2nd and 5th nodes measuring 60 cm. This distance represents 1.5 wavelengths, leading to a calculation of the original wavelength as 40 cm. The frequency of 100 Hz is not directly useful for determining wavelength without additional information about wave speed. Understanding that the distance between adjacent nodes is half the wavelength is crucial for solving the problem. The discussion highlights the importance of recognizing relationships between nodes and wavelengths in wave mechanics.
Saladsamurai
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It was only worth 5 points so I just guessed.

Two sinusoidal waves interfere with each other to produce a Standing wave. The distance between the 2nd and 5th node is 60cm. What was the original wavelength of the original waves?

Oh yeah, and f=100Hz.

Where do I start on this one. I know f=nv/2L and V=lambda*f

um...I guess I am missing whatever the key concept is here to establish the correct relationship.

Any ideas?

Casey
 
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The nodes are where the string (or whatever) is not moving. There are how many wavelengths in the 3 nodes as you go from the 2nd to the 5th node?
 
berkeman said:
The nodes are where the string (or whatever) is not moving. There are how many wavelengths in the 3 nodes as you go from the 2nd to the 5th node?

1.5 ? I am not sure what to do with this number. ...60/1.5=40cm?

Casey
 
Last edited:
But seriously...now what?
 
Saladsamurai said:
1.5 ? I am not sure what to do with this number. ...60/1.5=40cm?

Casey

That would be what I would put down. Do you know if it is correct?
 
berkeman said:
That would be what I would put down. Do you know if it is correct?

I don't know. So is the 100Hz just there to mess with me?
 
Saladsamurai said:
I don't know. So is the 100Hz just there to mess with me?

To test your thinking (aka mess with you). The 100Hz is no help in determining the wavelength unless you have what other two pieces of information about the string?
 
berkeman said:
To test your thinking (aka mess with you). The 100Hz is no help in determining the wavelength unless you have what other two pieces of information about the string?

If I had wave speed V... It did not say it was a string so in general I would have needed some representitive of its elasticity (tension or bulk modulus) and its inertia (linear or volumetric density) since V=\sqrt\frac{elasticity}{inertial}

Casey
 
Saladsamurai said:
1.5 ? I am not sure what to do with this number. ...60/1.5=40cm?

Casey

I agree too.

the distance between two adjacent nodes is half the wavelength of the two waves combining to give a standing wave pattern.
 
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