KCL: Circuits & Current - Need Help?

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The discussion revolves around understanding current flow at a specific node (Nd) in a circuit involving resistors R3, R4, R1, R2, and R5. The total current leaving Nd through R3 and R4 is 2 mA, while the incoming current from R1 and R2 is 4 mA. By applying Kirchhoff's Current Law (KCL), it is established that the current from R5 (I5) must be -2 mA, indicating it flows from bottom to top. This analysis clarifies the current distribution at the node and resolves the initial confusion regarding the current direction. Understanding KCL is essential for analyzing complex circuits effectively.
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In the given figure, at the node where R3 and R4 are connected (let us call this as Nd), the total current flowing out of the node through R3 and R4 is (4-2mA=2mA). Now there are two other paths joining at Nd. So the current from these two paths into the node Nd could be 4mA ( from R1 and R2 paths) and current from R5 path (let us call this as I5). Now applying KCL at node Nd, 4mA+I5=2mA , giving I5=-2mA, so I5 should flow from bottom to top.
 
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