Calculate Period of Planet X with Kepler's Third Law

AI Thread Summary
Kepler's Third Law relates the orbital period of a planet to its distance from the sun, stating that the square of the period (T) is proportional to the cube of the semi-major axis (R) of its orbit. For planet X, with an orbital radius twice that of Earth, the correct formula is TX^2 = (1 Year) x (RX/RE)^3. This indicates that the period of planet X can be calculated based on its distance relative to Earth's orbit. The discussion highlights confusion regarding the application of Kepler's Third Law and the need for clarity on its principles. Understanding this law is essential for calculating the orbital period of celestial bodies.
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Using Kepler's Third Law, give the formula for the period TX of planet X whose orbital radius RX is twice that of earth, RE.

A. TX=(1 Year)x(RX/RE)^3
B. TX^2=(1 Year)x(RX/RE)^3
C. TX=(1 Year)x(RE/RX)^3
D. TX^2=(1 Year)x(RE/RX)^3

My book is not giving me a formula to use, so i a totally stuck... and ideas?
 
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What does Kepler's third law say?
 
thats part of the problem, i don't know what it says
 

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