Kinda silly, but what's the sign of v?

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Homework Help Overview

The discussion revolves around the sign of velocity for a block attached to a spring, particularly when it returns to its relaxed position after being pulled and released. The context involves concepts from mechanics and energy conservation.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of the conservation of energy equation and question the sign of velocity based on the direction of motion. There is also a discussion about the nature of energy as a scalar quantity and its relation to direction.

Discussion Status

Some participants have offered guidance on defining axes and relating quantities to them, while others are questioning the assumptions about the sign of velocity and its implications for energy. Multiple interpretations of the problem are being explored.

Contextual Notes

There is a mention of a potential error in understanding the sign of velocity, as well as the need for a diagram to clarify the situation. The exercise provides specific values for k, mass, and x, but the participants indicate that the issue lies elsewhere.

0kelvin
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I have a block with a certain mass attached to a spring. I pull it and then release. Spring pulls block back. When spring is back to its relaxed position, is the velocity of the block positive or negative? Exercise does provide k, mass and x, but that's not where the error is coming from.

According to the law of conservation of energy I have:

$$\frac{1}{2}mv^2 = \frac{1}{2}kx^2$$

I imediately though that since the usual orientation is x is positive to the right and block is moving to the left, velocity should be negative. But there is an example like this in the book and velocity is positive. How so? Absolute value is right, but the sign is wrong.
 
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0kelvin said:
I have a block with a certain mass attached to a spring. I pull it and then release. Spring pulls block back. When spring is back to its relaxed position, is the velocity of the block positive or negative? Exercise does provide k, mass and x, but that's not where the error is coming from.

According to the law of conservation of energy I have:

$$\frac{1}{2}mv^2 = \frac{1}{2}kx^2$$

I imediately though that since the usual orientation is x is positive to the right and block is moving to the left, velocity should be negative. But there is an example like this in the book and velocity is positive. How so? Absolute value is right, but the sign is wrong.

Just define your axes and relate all quantities to them. Can you post a diagram so we can help clarify your question?
 
Whether v is positive or negative, what is the sign of v2 ?
 
This is how I think about it. Since we have T=1/2mv^2, T is nothing more than energy. Is energy a scalar or vector? It's a scalar, has no direction. So I believe energy doesn't have a direction so the negative sign will disappear. I used T instead of V since we use T a lot in dynamics.
 

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