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P944
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Homework Statement
I am having a heck of a time trying to solve these problems. Please help if you can.
A hot air balloon has just lifted off and is rising at the constant rate of 2.4 m/s. Suddenly, one of the passengers realizes she has left her camera on the ground. A friend picks it up and tosses it straight upward with an initial speed of 11.6 m/s. If the passenger is 2.5 m above her friend when the camera is tossed, how high is she when the camera reaches her?
Homework Equations
v= v0 +a*t
x=x0 + vt - 1/2*a*t^2
x=x0 + v0*t +1/2at^2
v^2 =V0^2 +2a(x-x0)
The Attempt at a Solution
I tried to solve for time then use that variable to solve for distance
V=Vo + at = 0=11.6m/s +(-9.80m/s^2)*t
1.184s = time
x = x0 +vt - 1/2at^2
x = 2.5m + (1.184s)(11.6m/s) - 1/2(-9.80m/s^2)(1.184s)^2 = 23.10
I would greatly appreciate if someone could help me understand where i went wrong or understand how to approach this problem. thank you so much
… that's the time it reaches maximum height (v = 0), you need the time it passes the balloon. 
