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A neutron (mass 1 u) experiences an elastic head-on collision with a gold nucleus (mass 197 u) that is originally at rest. What percentage of its original kinetic energy does the moving particle lose?

## Homework Equations

Elastic Collision:

V1f= (m1-m2)/(m1+m2) * V1i

K.E. = 1/2 m*v^2

## The Attempt at a Solution

The final Velocity of the moving particle is (1u-197u/198u) *V1i

But I don't know where to go from here in terms of solving the percentage of Kinetic Energy lost.