Kinetic energy of a recoiling nucleus

roughtenator
Messages
3
Reaction score
0
A Fe nucleus at rest emits a 14.0-keV photon. Use conservation of energy and momentum to deduce the kinetic energy of the recoiling nucleus in electron volts. (Use Mc2 = 8.60E-9 J for the final state of the Fe nucleus.)
what I have so far is...

E = pc because E >> photon rest energy , which = 0 eV

P = E/C = 7.476 E-24

P1 = P2

I'm not sure what to do next.

Thanks in advance for the help!
 
Physics news on Phys.org
what is the relation between Energy and kinetic energy in special relativity? And what is the relation between energy, momentum and mass in special relativity?
 
Relation between kinetic energy and total energy in special relativity is...
E = K + mc2
Relationship between mass, energy and momentum is...
E2 = P2C2 + (mc2)2
 
great, then can you find, from these two, a relation between momentum, mass and kinetic energy?
 
is this valid?

(K+MC2) = P2C2 + (MC2)2

then isolate K?
 
you forgot to square the left-hand side ...
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top