Kinetic Energy Homework: Solving Problems with Velocity and Potential Energy"

AI Thread Summary
The discussion focuses on solving kinetic energy problems involving velocity and potential energy, specifically analyzing two stones in motion. For the first stone, understanding its movement at maximum height is crucial, as it emphasizes the forces acting on it at that instant. The second stone's motion requires breaking down its initial velocity into horizontal and vertical components, highlighting the importance of projectile motion principles. Participants are encouraged to attempt the problems independently before reviewing provided solutions. This approach fosters a deeper understanding of the concepts involved in kinetic energy and motion.
epix
Messages
3
Reaction score
0

Homework Statement



[PLAIN]http://img218.imageshack.us/img218/249/photoxl.jpg

Homework Equations



vmax = Sq(2gh)
Ei=Ef
mgh=mgh+.5mv^2
 
Last edited by a moderator:
Physics news on Phys.org
For the first stone, how is it 'moving' at it's max height? Think about how the forces are acting and how the stone would be moving at the INSTANT it reaches its max height, this should give you a good hint as to how to treat the second stone.

For the case of the second stone you need to break it down into horizontal and vertical components. The motion of the second stone isn't entirely in the vertical direction, there is also a component in the horizontal direction. Break the initial velocity Vo into its vertical and horizontal components. What is 1 significant thing to remember about projectile motion? Apply that to find your solution.
 
Attached is my solution to the two questions. I strongly suggest you try to solve the problems on your own before going through my solution.
 

Attachments

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top