Kinetic energy, special relativity

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
5 replies · 5K views
fluidistic
Gold Member
Messages
3,934
Reaction score
286

Homework Statement



Calculate the kinetic energy of an electron whose momentum is 2MeV/c.

Homework Equations


[tex]P=\gamma m_0 v =mv[/tex].
[tex]E_K=(m-m_0)c^2[/tex].

The Attempt at a Solution


I'm told that [tex]\gamma m_0 v=\frac{2MeV}{c}[/tex].
If only I had the mass at rest of the electron (it isn't given in the problem), I could calculate its velocity with the first formula I gave. Then I could calculate its mass (not its rest mass, its apparent mass or whatever it's called). And then I could apply the third formula and this would solve the problem. Am I right?
So, should I look for the electron's rest mass in some book? Is there a missing data, or can I solve the problem without this info?
 
Physics news on Phys.org
You can do that. But you shouldn't have to look anything up. Do you know the relationship between [tex]\lambda[/tex] (the lorentz factor) and v? if so, solve for the rest mass. Similarly, you can find the relationship between [tex]m[/tex] and [tex]m_0[/tex]. I hope that helps!
 
Last edited:
aq1q said:
You can do that. But you shouldn't have to look anything up. Do you know the relationship between [tex]\lambda[/tex] (the lorentz factor) and v? if so, solve for the rest mass. Similarly, you can find the relationship between [tex]m[/tex] and [tex]m_0[/tex]. I hope that helps!

I appreciate very much your help.
What I know is [tex]\gamma =\frac{1}{\sqrt {1-\frac{v^2}{c^2}}}[/tex]. I don't know how to solve for the rest mass since v is unknown. I get [tex]m_0=\frac{P}{v}\sqrt {1-\frac{v^2}{c^2}}[/tex] where P and c are known but not v...
 
ahh what was i thinking. you're right! you need to look up the rest mass. I'm really sorry, at a quick glance I thought this was just algebra.
 
aq1q said:
ahh what was i thinking. you're right! you need to look up the rest mass. I'm really sorry, at a quick glance I thought this was just algebra.
Ok thanks for your help. Problem solved!
 
fluidistic said:
Ok thanks for your help. Problem solved!

great!