When mass M is at the position shown, it is sliding down the inclined part of a slide at a speed of 1.89 m/s. The mass stops a distance S2 = 1.85 m along the level part of the slide. The distance S1 = 1.25 m and the angle theta = 37.7 degrees. Calculate the coefficient of kinetic friction for the mass on the surface. Well i kinda found a formula for this by changing the conservatiion of energy(K_f+U_f=K_i+U_i+W_nc). The formula is mu_k=(-1/2*(V_i^2)-1/2*(g*h))/(g*S_total), But I still dont get the right answer am I doing something wrong?