- #1
mixedtape_15
- 12
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Kinetic Friction Problem..Need Help!
Okay...so I really think I'm doing this right..but the CAPA thing won't take my answer so there has to be something I'm doing wrong.
The Question is ...
A 32.0 kg box is being pulled along a horizontal surface by means of a rope that exerts a force of 265 N at an angle of 54.5o above the horizontal. The coefficient of kinetic friction between the box and the surface is 0.330. What is the acceleration of the box?
So I drew my free body diagram and I had the Normal Force and the Weight and cosine of the angle in the y direction and I had the kinetic friction (normal force times kinetic friction coefficient) and weight and sine of the angle in the X direction.
Then I worked it all out and I got
Fy = may
Fy = 0
N - W(cos54.5) = 0
N - mg(cos54.5) = 0
N = 32.0kg (9.81 m/s^2)(cos54.5)
N = 182.3
Fx = max
-fk + T - w(sin54.5) = max
T - (N x uk) - mg(sin54.5) = max
265 - (182.3 x 0.330) - (32kg)(9.81m/s^2)(sin54.5) = 32kg(ax)
then I solved It all and it worked out to be -1.59 m/s^2
but its saying its not right..so I'm confused beyond belief now.
so Please help me .. lol
Okay...so I really think I'm doing this right..but the CAPA thing won't take my answer so there has to be something I'm doing wrong.
The Question is ...
A 32.0 kg box is being pulled along a horizontal surface by means of a rope that exerts a force of 265 N at an angle of 54.5o above the horizontal. The coefficient of kinetic friction between the box and the surface is 0.330. What is the acceleration of the box?
So I drew my free body diagram and I had the Normal Force and the Weight and cosine of the angle in the y direction and I had the kinetic friction (normal force times kinetic friction coefficient) and weight and sine of the angle in the X direction.
Then I worked it all out and I got
Fy = may
Fy = 0
N - W(cos54.5) = 0
N - mg(cos54.5) = 0
N = 32.0kg (9.81 m/s^2)(cos54.5)
N = 182.3
Fx = max
-fk + T - w(sin54.5) = max
T - (N x uk) - mg(sin54.5) = max
265 - (182.3 x 0.330) - (32kg)(9.81m/s^2)(sin54.5) = 32kg(ax)
then I solved It all and it worked out to be -1.59 m/s^2
but its saying its not right..so I'm confused beyond belief now.
so Please help me .. lol