Kinetics of Rigid Bodies: Torque and Acceleration Calculation

AI Thread Summary
To calculate the torque required to accelerate a 200 kg rotor from rest to 1,500 rev/min in 6 seconds, the moment of inertia (I) is determined using the formula I = 1/2 (mr^2), but the radius of gyration must be correctly interpreted. The correct calculation for I involves using the radius of gyration, which is not the same as the physical radius of the rotor. Angular acceleration (α) can be found using kinematic equations for rotational motion, ensuring proper unit conversions. Once α is known, torque can be calculated using the equation ƩMO = Iα. The discussion emphasizes the importance of understanding the relationship between linear and rotational motion equations.
Rob K
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Homework Statement


The rotor of an electric motor of mass 200 kg has a radius of gyration of 150 mm. Calculate the torque required
to accelerate it from rest to 1,500 rev/min in 6 seconds. Friction resistance may be neglected.

Homework Equations


ƩMO = Iα
I = 1/2 (mr2
I am really really stuck here, I don't know what equations I need to use, if this were a straight line question I would use v = u + at, but it isn't so that is wrong


The Attempt at a Solution


All I have so far is this
I = 1/2 (mr2
I = 0.5 * 200 * 0.152
I = 2.25 kgm2

Really lost. I just need some pointers please.

Kind regards

Rob
 
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In calculating I, the radius of gyration is not the radius of a disk. You can look up the formula for it, which is r = \sqrt{I/m} (and note how it is derived).

You can find the angular acceleration α using the kinematic equations of rotational motion (watch units).
 
Brilliant, those are the words I didn't know to find the equation I couldn't find of variables I couldn't relate.

Found them all.

Thank you
 
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