- #1
jisbon
- 476
- 30
- Homework Statement
- Two parallel rails with negligible resistance are 10.0 cm apart and are connected by a 5.00 resistor. The circuit also contains two metal rods having resistances of R = 10.0Ω and 15.0 Ω sliding along the rails. The rods are pulled to the right at constant speeds 4.00 m/s and 2.00m/s, respectively. A uniform magnetic field of magnitude 0.0100 T is applied perpendicular to the plane of the rails. Determine the magnitude and direction of the current in the 5.00 Ωresistor
- Relevant Equations
- I'm not totally sure on this.
So I was checking this question out, and I saw that someone did discuss about a similar question before on this forum here:
https://www.physicsforums.com/threads/did-i-get-it-right-by-coincidence.487088/
Since this is a different question, I would like to ask if anyone here could help me check my equation from my understanding (or at least what I thought), here is the diagram:
So applying junction rule,
Black arrow = I1
Green arrow = I2
Red arrow = I3
[tex]I1= I2+ I3[/tex]
Now applying the other rule aka the loop rule:
My left loop will be:
[tex]-I1(10) - I3(5) - BLV1 = 0[/tex]
?
My right loop will be:
[tex]I2(15)-I3(5)-BVL2 = 0[/tex]
?
I'm not entirely sure how the loop goes about when there's a magnetic field (only dealt with them in normal circuits), so any assistance will be greatly appreciated. Cheers!
https://www.physicsforums.com/threads/did-i-get-it-right-by-coincidence.487088/
Since this is a different question, I would like to ask if anyone here could help me check my equation from my understanding (or at least what I thought), here is the diagram:
So applying junction rule,
Black arrow = I1
Green arrow = I2
Red arrow = I3
[tex]I1= I2+ I3[/tex]
Now applying the other rule aka the loop rule:
My left loop will be:
[tex]-I1(10) - I3(5) - BLV1 = 0[/tex]
?
My right loop will be:
[tex]I2(15)-I3(5)-BVL2 = 0[/tex]
?
I'm not entirely sure how the loop goes about when there's a magnetic field (only dealt with them in normal circuits), so any assistance will be greatly appreciated. Cheers!
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