Kortweg-de Vries: Parabolic PDE Homework

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Homework Statement



The equation is ut + uux + uxxx = 0

I need to show that this is a parabolic pde.

Homework Equations



Hint : convert to an equivalent system of 1st order equations by introducing an auxiliary variable p = ux, etc.

The Attempt at a Solution



So i took p = ux

doesn't that just give me:

ut + pu + pxx = 0

This i think is a parabolic pde by inspection.

But the hint says i need to get a system of 1st order equations. What am i missing? I am pretty sure I've made a giant error. Help please!
 
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So introduce another variable v=\partial_{x}p and you have a system.
 
How would that help? I don't get it.
Can you please elaborate?
 
Your system of equations is:
<br /> \begin{array}{ccc}<br /> v &amp; = &amp; \partial_{p} \\<br /> p &amp; = &amp; \partial_{x}u \\<br /> \partial_{t}u+pu+\partial_{x}v &amp; = &amp; 0<br /> \end{array}<br />

This system can be written in the form:

<br /> \mathbf{A}\partial_{t}\mathbf{U}+\mathbf{B}\partial_{x}\mathbf{U}=\mathbf{c}<br />

Now the condition for parabolic equation comes in with the determinants of A and B (look this up, this should be in your notes)
 
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