Laplace Transform (Linear Algebra)

yesiammanu
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Homework Statement


Evaluate the laplace transform of {t2e7tsinh(3t)}


Homework Equations


Laplace transform of {tnf(t)}=(-1)ndn/ds2 * F(s)


The Attempt at a Solution


I've replaced it with (-1)2d2L{e7tsinh(3t)}

I'm not sure how to proceed, though, as I don't really see how to take the laplace without somehow splitting up these functions. Do I use a unit step function? How would I use it if so? I'm not really sure what to do here

Thanks for any help.
 
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The Laplace transform of a function that has been multiplied by an exponential function can be found using the shift theorem for the s-axis. Do you know this theorem?

BiP
 
Is this the theorem you were referring to?

L{e-asF(s)}=f(t-a)*UnitStep(t-a)
 
yesiammanu said:

Homework Statement


Evaluate the laplace transform of {t2e7tsinh(3t)}


Homework Equations


Laplace transform of {tnf(t)}=(-1)ndn/ds2 * F(s)


The Attempt at a Solution


I've replaced it with (-1)2d2L{e7tsinh(3t)}

I'm not sure how to proceed, though, as I don't really see how to take the laplace without somehow splitting up these functions. Do I use a unit step function? How would I use it if so? I'm not really sure what to do here

Thanks for any help.

You can write ##\sinh(3t) = \frac{1}{2} \left( e^{3t} - e^{-3t}\right),## and proceed accordingly.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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