Lateral compression of rectangular tube

AI Thread Summary
To calculate the stress and safe working load of a stainless steel rectangular tube under a 10,000kg weight, a shear stress calculation is recommended, particularly focusing on local failure modes such as bending and buckling. The force divided by the area provides a basic understanding, but finite element stress analysis may be necessary for more accurate results. The effective width of each face should be considered when assessing potential failure points. While simplified calculations can be useful, they may not capture the complexities of the loading on hollow sections. Ultimately, a thorough analysis is essential for ensuring safety in the design.
Colnago
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Hi guys,

Bit of a noob engineer here so looking for some guidance.

I'm designing a fixture which will be constructed from stainless steel rectangular tube as shown in the diagram. If I apply a 10,000kg weight over a 100mx100mm area how do I go about calculating the stress and ultimately safe working load?

The tube will be laid flat on the ground. Is this just a case of force/area? I'm struggling to find any textbook examples of loading applied to hollow sections in this way.

Thanks in advance!

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You probably need to do some finite element stress analysis. I can't think of a way of simplifying it. Maybe someone else can.

Chet
 
Hi Colnago,

I'm no structural engineering expert but I would start with a shear stress calculation. Check the following link under the heading 'Beam shear' for an equation:

http://en.wikipedia.org/wiki/First_moment_of_area#Statical_moment_of_area

The equation is usually used for simply supported beams, rather than one which is supported throughout it's whole length but I think it is still valid. Maybe someone else could confirm.
 
Assuming we are talking about a local failure here and not a larger beam failure.

I see two possible local failures:
1) the horizontal face failing by bending
2) the vertical faces failing by buckling or crippling

You would have to make an assumption about the effective width of each face. You could come up with a less conservative design with FEM but probably not worth the effort practically.
 
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