LC/Resonant circuit - the maximum capacitor energy

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Homework Help Overview

The discussion revolves around calculating the maximum energy stored in a capacitor within an LC circuit, given an effective voltage and capacitance. The subject area includes concepts of energy storage in capacitors and the interpretation of voltage in AC circuits.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between effective voltage and peak voltage in the context of energy calculations. There is a debate on whether the term "effective" refers to RMS voltage and how that impacts the energy calculation.

Discussion Status

The discussion is ongoing, with participants questioning the terminology used in the problem statement and its implications for the calculations. Some guidance is offered regarding the definitions of voltage types, but no consensus has been reached on the correct interpretation or calculation method.

Contextual Notes

There is uncertainty regarding the author's choice of terminology, particularly the use of "effective" in relation to AC voltage, which may lead to different interpretations of the problem. Participants are also considering the implications of using RMS values versus peak values in their calculations.

fawk3s
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Homework Statement



The effective voltage in an LC circuit is 200V while the capacitance of the capacitor in the circuit is 20pF. What is the maximum capacitor energy?

Homework Equations



We = CU^2/2

Uefective = U / sqrt(2)

The Attempt at a Solution



Well it seems a fairly simple problem. It solves by just calculating the energy by putting the given information in the energy equation above, and the answer is supposed to be 4*10^-7 J.
However, this is not the way I solved it. As it states in the problem, the effective voltage of the system is supposed to be 200V, as there is AC going through it. So shouldn't we calculate the peak voltage first, which is 200*sqrt(2) and use it to calculate the maximum energy of the capacitor, which would be when the capacitor is fully charged and there is no current goingh through the system? By doing this we get the answer to be 8*10^-7 J.

So where does my logic fail?

Thanks in advance,
fawk3s
 
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I suspect that the author of the problem made a poor choice in using the word "effective" here, and didn't realize that it could be taken to have the connotation of RMS value.
 
English is not my native language, but I am pretty certain he intended to use these words, as in the effective value of the AC voltage. Now does my logic fail somewhere or did the author make a mistake (which is highly unlikely)?
Because by my logic, the maximum voltage on the charged capacitor (when there is currently no current in the system) should be equal to the peak voltage of the AC voltage, not the effective value of the AC voltage.

Thanks in advance,
fawk3s
 
The energy stored in a capacitor is

[tex]\xi = \frac{1}{2} C\; V^2[/tex]

Where V is the voltage on the capacitor (Joules/Coulomb). There's no quibbling about that. Since there's no concept of "effective energy", the answer should use the actual instantaneous voltage on the capacitor to calculate the stored energy.

So either the author's choice of word was poor, or his answer is wrong. Your choice!

Edit: Maybe I spoke to soon. After thinking about it, it might not be unreasonable to speak of the RMS energy handled by the capacitor in some context. But still, this would not be the maximum capacitor energy.
 
Last edited:

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