Learning Physics 014 & 015: Find Acceleration

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The discussion focuses on calculating tangential and total acceleration for a point on a rotating turntable. The point starts from rest and reaches a speed of 0.958 m/s in 1.95 seconds, with the radius being 0.131 m. Participants discuss the formulas for tangential acceleration and centripetal acceleration, emphasizing the need to determine the speed at t1 = 1.6 s to apply these formulas effectively. There is a recognition of the constant rate of change in speed during the time interval. The conversation highlights the learning process involved in understanding these physics concepts.
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014 (part 1 of 2) 10 points
The speed of a point on a rotating turntable,
which is 0.131 m from the center, changes at a
constant rate from rest to 0.958 m/s in 1.95 s.
At t1 = 1.6 s, find the magnitude of the
tangential acceleration. Answer in units of
m/s2.
015 (part 2 of 2) 10 points
At t1 = 1.6 s, ¯find the magnitude of the total
acceleration of the point. Answer in units of
m/s2.
 
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i know the formulas ... .

v = 2pi r/t

centripital acceleration = v2/r

not sure if they help me on this one tho
 
changes at a constant rate from rest to 0.958 m/s in 1.95 s.
At t1 = 1.6 s, find the magnitude of the tangential acceleration.

So the rate is constant during the 1.95 s and one needs to find speed at 1.6 s and from this v2/r.
 
really? wow. I am just learning too... lol
 
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