Least distance between two complex numbers on two loci

AI Thread Summary
The discussion revolves around solving a CIE A'level maths problem involving the least distance between two complex numbers on specified loci: a circle centered at (0,-1) with a radius of 1 and a line at 135 degrees to the horizontal starting from x=2. Participants share their solutions and methods, with one suggesting a calculus-based approach to minimize the distance |z-w|, while another highlights a geometric method involving rotation for simplification. The conversation emphasizes the importance of understanding both geometric and calculus techniques for tackling such problems. Overall, the exchange provides insights into different strategies for solving complex number distance problems.
moriheru
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Homework Statement


This is a CIE A'level maths P3 question out of an exam from 2013 in October/November. As there is no markscheme ( I at least can't find one), I would be grateful if someone could look at my solution to the problem and correct me if I made a mistake.
The problem is 8.(b) below.
IMG_1880.PNG

Homework Equations

The Attempt at a Solution


The first locus they are asking for is that of a circle with centre (0,-1) and radius 1 and the second locus is a line 135 deg. to the horizontal (real number axis) starting at x=2. I call z1 and z2 the points which will give the least value of abs(z-w). Both these points must lie on a line l2. My further working and sketch of loci and the line are in the following image.In the last step I use the distance formula for the two complex numbers I calculated in the earlier steps. In the earlier steps I equated the equation of l2 and the equations for the loci.
IMG_1908.JPG


Thanks for any effort! And sorry for the clumsy exposition!
 
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moriheru said:

Homework Statement


This is a CIE A'level maths P3 question out of an exam from 2013 in October/November. As there is no markscheme ( I at least can't find one), I would be grateful if someone could look at my solution to the problem and correct me if I made a mistake.
The problem is 8.(b) below.
View attachment 195845

Homework Equations

The Attempt at a Solution


The first locus they are asking for is that of a circle with centre (0,-1) and radius 1 and the second locus is a line 135 deg. to the horizontal (real number axis) starting at x=2. I call z1 and z2 the points which will give the least value of abs(z-w). Both these points must lie on a line l2. My further working and sketch of loci and the line are in the following image.In the last step I use the distance formula for the two complex numbers I calculated in the earlier steps. In the earlier steps I equated the equation of l2 and the equations for the loci.
View attachment 195848

Thanks for any effort! And sorry for the clumsy exposition!
I get the same result. You can simplify it to √2 + 1/√2 - 1
 
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Thanks! That is great! Is my method correct and is there any general method how to approach these problems geometrically or is it just case by case observation? I know of a calculus based approach. As far as I know one expresses abs(z-w) in terms the general coordinates of any point on the loci and then sets the derivative equal to zero. Is this correct? And how would the general form for abs(z-w) look like? Thanks for any further effort?
 
moriheru said:
is there any general method how to approach these problems geometrically or is it just case by case observation?
A general method (not just circles and lines) will necessarily be by calculus. Of course, minimising |z-w| is the same as minimising |z-w|2, which simplifies things a little.
In many cases, it will be a bit easier with a geometric approach. In this one, I did it by rotating the circle's centre through 45 degrees about the origin. Then I only needed the horizontal distance from the circle to the line x=√2.
 
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Thanks a lot ! And interesting approach. I will keep that in mind.
 
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