Let f(x)=3x^2+6x-10For which input x is the value of the function a minimum?

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For the quadratic function f(x) = 3x^2 + 6x - 10, the minimum value occurs at the stationary point calculated using x = -b/2a. Since the coefficient of x^2 (a) is positive, this formula indicates that the function has a minimum. The value of x that minimizes the function is found by substituting a = 3 and b = 6 into the formula, resulting in x = -1. The minimum value of the function can be determined by evaluating f(-1), which yields f(-1) = -13. Thus, the function achieves its minimum value of -13 at x = -1.
Jurrasic
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And what is the minimum value?
( -b/2a is for a maximum problem, but how do you get through this kind of problem?)
 
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x=-b/2a will give you the stationary point for the quadratic. In f(x) =ax^2+bx+c, if a>0 is the stationary point maximum or minimum?
 
Jurrasic said:
And what is the minimum value?
( -b/2a is for a maximum problem, but how do you get through this kind of problem?)
For the quadratic, ax2 + bx + c:

If the coefficient of x2, which is a, is negative, then x = -b/2a, gives the x coordinate of the maximum.

If the coefficient of x2, which is a, is positive, then x = -b/2a, gives the x coordinate of the minimum.
 
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