Light Bulbs in Series vs. Parallel

AI Thread Summary
Connecting a 25W and a 100W light bulb in series across a 240V power line leads to one bulb burning out due to excessive power consumption. In a series circuit, the same current flows through both bulbs, and their resistances can be calculated from their ratings. When the total current is determined, the power consumed by each bulb can be compared to its rated power. The bulb with the lower wattage rating, the 25W bulb, will exceed its power limit and burn out first. Understanding the relationship between power, current, and resistance is crucial for analyzing such circuits.
kimberlyann9
Messages
12
Reaction score
0

Homework Statement


You have two 120V light bulbs, one 25W and one 100W, that are normally connected in parallel with 120V across each. Your friend had what seemed like a good idea which was to connect them in series across a 240V power line. However, one of them burned out immediately. Which one burned out and why?


Homework Equations


P=IV
P=I^2*R


The Attempt at a Solution


If light bulbs are in series, the same current flows through both of them. Should I treat this like a resistor problem and calculate the resistor of the light bulbs in both cases? I'm not sure how to figure out which one burns out.
 
Physics news on Phys.org
kimberlyann9 said:

Homework Statement


You have two 120V light bulbs, one 25W and one 100W, that are normally connected in parallel with 120V across each. Your friend had what seemed like a good idea which was to connect them in series across a 240V power line. However, one of them burned out immediately. Which one burned out and why?


Homework Equations


P=IV
P=I^2*R


The Attempt at a Solution


If light bulbs are in series, the same current flows through both of them. Should I treat this like a resistor problem and calculate the resistor of the light bulbs in both cases?
Yes.
I'm not sure how to figure out which one burns out.
As you stated, first calculate the resistance for each bulb in the 120 volt circuit. The resistances of your light bulbs are fixed values. Then putting them in series with 240 volt source, you will find the total system current. From that you can determine the power consumed by each bulb. Comparing the calculated power of each bulb with it's rating will make it obvious which one would burn out.
 
OmCheeto said:
Yes.

As you stated, first calculate the resistance for each bulb in the 120 volt circuit. The resistances of your light bulbs are fixed values. Then putting them in series with 240 volt source, you will find the total system current. From that you can determine the power consumed by each bulb. Comparing the calculated power of each bulb with it's rating will make it obvious which one would burn out.

Okay great, thanks for your help!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top