Lim sups and lim infs homework

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Homework Statement



http://i.imgur.com/ARy65.png

Homework Equations



Just general definitions of lim sups and lim infs

The Attempt at a Solution



I'm stuck on the part a. I realize that since a_n has a limit that means it is bounded and monotone. By I don't know how that implies that b_m is nonincreasing. The way I understand b_m is that b_1 = sup{a_m} and b_2 = sup{a_m,a_(m+1)} so is that correct? If so doesn't it depend on whether or not a_m is less than or greater than a_(m+1) and so on to know that b_m is nonincreasing?
 
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koshn said:
I'm stuck on the part a. I realize that since a_n has a limit that means it is bounded and monotone. By I don't know how that implies that b_m is nonincreasing. The way I understand b_m is that b_1 = sup{a_m} and b_2 = sup{a_m,a_(m+1)} so is that correct? If so doesn't it depend on whether or not a_m is less than or greater than a_(m+1) and so on to know that b_m is nonincreasing?

No, an is not assumed to converge (unless I missed something). The limsup is defined for any sequence, even divergent ones (although then sometimes the limsup may be infinity).

I don't think you totally understand the bm. The way bm is defined would give

<br /> b_1 = \sup\{a_1, a_2, a_3, a_4 \ldots\} <br />
<br /> b_2 = \sup\{a_2, a_3, a_4 \ldots\}<br />
<br /> b_3 = \sup\{a_3, a_4 \ldots\}<br />

,etc. Basically, as m increases, the first m terms of (an) are omitted when taking the sup. Now take another look at the hint. Does that help?
 
koshn - What definition of lim sup are you using? I ask because part (d) is often given as the definition of lim sup, whereas you are being asked to prove it.
 
spamiam said:
No, an is not assumed to converge (unless I missed something). The limsup is defined for any sequence, even divergent ones (although then sometimes the limsup may be infinity).

I don't think you totally understand the bm. The way bm is defined would give

<br /> b_1 = \sup\{a_1, a_2, a_3, a_4 \ldots\} <br />
<br /> b_2 = \sup\{a_2, a_3, a_4 \ldots\}<br />
<br /> b_3 = \sup\{a_3, a_4 \ldots\}<br />

,etc. Basically, as m increases, the first m terms of (an) are omitted when taking the sup. Now take another look at the hint. Does that help?

Thanks that helped to clear the confusion I was having.

jbunniii said:
koshn - What definition of lim sup are you using? I ask because part (d) is often given as the definition of lim sup, whereas you are being asked to prove it.

The definition I'm using is that lim sup x_n is defined to be the infimum of all numbers b with the following property: There is an integer N so that x_n < b for all n >= N.
 
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