Limit of u(t)- u(t -\delta) as delta goes to zero, LTI systems

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The limit of yb(t) as delta approaches zero involves evaluating the expression (b/delta)*exp[-t/RC](exp[delta/RC] - 1) using L'Hôpital's rule, resulting in exp[-t/RC]/RC. The challenge arises with the term u(t) - u(t - delta), leading to uncertainty about its behavior as delta approaches zero. It is suggested that this term may relate to the Dirac delta function, prompting a discussion on the derivative of the unit step function u(t). Clarification is sought on whether to interpret the limit as approaching zero or as a representation of the delta function. Understanding these concepts is crucial for solving the problem effectively.
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Homework Statement



what is the limit of yb(t) as \delta goes to zero.

yb(t) = (b/delta)*exp[-t/RC](exp[delta/RC] - 1)(u(t)-u(t-delta))

b=1.






2. The attempt at a solution

I used L'hopitals rule to find the limit of (b/delta)*exp[-t/RC](exp[delta/RC] - 1), which i got to be exp[-t/RC]/RC.

But I do not know what to do with the u(t)-u(t-delta). does it go to zero? or am I supposed to say it goes to delta(t)?

Any help/ advice would be appreciated, thanks!
 
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Does the expression

\lim_{\delta \to 0} \frac{u(t + \delta) - u(t)}{\delta}
ring a bell?
 
honestly, no. I'm fairly new to the unit step and dirac delta function.
 
Oh, but this doesn't have to do with either of those. \delta is just a variable, if it makes you feel any better you can call it x or (more commonly used) h

Maybe I should ask it the other way around: what is the definition of the derivative u'(t) of u(t) at t?
 

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