Limits question and finding oblique asymptote

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Question: Guess the oblique asymptote of the graph f(x) for x→∞. Write down the limit you have to compute to prove that your guess is correct.

f(x)= \sqrt{(x^{4}+1)/(x^{2}-1)}
so the limit would be: lim x→∞ \sqrt{(x^{4}+1)/(x^{2}-1)}

I sketched out a graph but I just have no clue how to compute for the oblique asymptote. The professor explained that you have to use the polynomials in long division but I don't fully understand how to yet.
 
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dustinm said:
Question: Guess the oblique asymptote of the graph f(x) for x→∞. Write down the limit you have to compute to prove that your guess is correct.

f(x)= \sqrt{(x^{4}+1)/(x^{2}-1)}
so the limit would be: lim x→∞ \sqrt{(x^{4}+1)/(x^{2}-1)}

I sketched out a graph but I just have no clue how to compute for the oblique asymptote. The professor explained that you have to use the polynomials in long division but I don't fully understand how to yet.

An oblique asymptote is a straight line y = ax + b that the graph of the function approaches for large x or very negative x.

Use polynomial long division to carry out the division of the rational expression inside the radical. You should get x2 + some other terms. Then, factor out x2 from each term inside the radical so that you have x2(1 + <other stuff>). At this point you can simplify the radical somewhat.

I'm sure there's a topic on wikipedia for polynomial long division. Open wikipedia and do a search using "polynomial long division" if you don't understand this process.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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