Line Integral Along a Path: How to Compute and Use Vector Fields

idir93
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1. Homework Statement

Vector field is F=-y\hat{x} + x\hat{y}

Compute the line integral along the path c(t)=( cos(t), sin(t) ) with 0≤t≤∏2. The attempt at a solution
i started computing f.dl but how much is dl ? I took it dx\hat{x} +dy\hat{y} I'm not sure if using Cartesian coordinates is right ?
 
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I can's see why you would say " I'm not sure if using Cartesian coordinates is right" when everything is given in Cartesian coordinates. You are given that the line is defined by c(t)= (cos(t), sin(t)) so it should be clear that dc= (-sin(t), cos(t))dt and that is dl because it has unit length.
 
Found it ! it's 0.5∏
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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