Linear algebra adjoint, determinant

Mdhiggenz
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Homework Statement



Given A=[1 2 1; 0 4 3; 1 2 2]
determine the (2,3) entry of A-1 by computing a quotient of two determinants.

This problem confused me a bit, do they just want us to divide the adj(A) by the det(A) in order which would give us A-1 and just state the (2,3) entry from there?

Thanks

Higgenz



Homework Equations





The Attempt at a Solution

 
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Mdhiggenz said:

Homework Statement



Given A=[1 2 1; 0 4 3; 1 2 2]
determine the (2,3) entry of A-1 by computing a quotient of two determinants.

This problem confused me a bit, do they just want us to divide the adj(A) by the det(A) in order which would give us A-1 and just state the (2,3) entry from there?

Thanks

Higgenz

Homework Equations


The Attempt at a Solution


You don't need to compute the whole A^(-1). But as you say, they just want you to compute adj(A)(2,3)/det(A). Just the one entry of A^(-1).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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