Linear Algebra (Similar Matrices)

[DanielFaraday]

Homework Statement

Write the standard matrix representation T_E for T.

Homework Equations

<br /> T\left(ax^3+bx^2+cx+d\right)=(a-b)x^2+(c-d)x+(a+b-c)<br />

The Attempt at a Solution

<br /> [T]_E=\left(<br /> \begin{array}{c}<br /> a+b-c \\<br /> c-d \\<br /> a-b \\<br /> 0<br /> \end{array}<br /> \right)<br />

I think this is right, but a subsequent problem asks me to show that this matrix is similar to another matrix. Similarity only makes sense for an n x n matrix, so this must be wrong.

Any ideas?

 

[Dick]

The basis 'vectors' are x^3, x^2, x and 1. So ax^3+bx^2+cx+d=(a,b,c,d).This is exactly the same as other exercises you have already done, it's T(a,b,c,d)=(0,a-b,c-d,a+b-c). Sure, it's an 4x4 matrix.

 

[HallsofIvy]

Is T here a function from the space of polynomials of degree 3 or less to itself or to the space of polynomials of degree 2 or less? If the former, the matrix is 4 by 4. If the latter, it is 4 by 3 (but the first row is all "0"s).
For example, taking x³ as the first "basis vector", T(x³)= ax²+ 0x+ a as a polynomial of degree 2 or less or 0x³+ ax²+ 0 x+ a as a polynomial of degree 3 or less. That is:
T\begin{bmatrix}1 \\ 0 \\ 0 \\ 0\end{bmatrix}= \begin{bmatrix}a \\ 0 \\ a\end{bmatrix}
in the first case or
T\begin{bmatrix}1 \\ 0 \\ 0 \\ 0\end{bmatrix}= \begin{bmatrix}0 \\ a \\ 0 \\ a\end{bmatrix}
in the second.

Do you see that those give you the first column of the matrix?

 

[DanielFaraday]

Ah yes, I see. I was thinking of T as a vector instead of a transformation. Thanks!