Linear Algebra: Solving a Matrix Equation for X

Mdhiggenz
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Homework Statement


The question and my work is in the image it is pretty much to solve for X.
Solve the following matrix equation
23if1tx.jpg

Not quite sure how I keep messing this problem up.

Homework Equations


The Attempt at a Solution

 
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Mdhiggenz said:

Homework Statement


The question and my work is in the image it is pretty much to solve for X.

Not quite sure how I keep messing this problem up.

Homework Equations





The Attempt at a Solution


The image you posted was too large (1599 pixels x 956 pixels), so I deleted it. Please reformat your image so that it is about 800 x 600.

Also, include the given information, preferably as text in this window.
 
Mark44 said:
The image you posted was too large (1599 pixels x 956 pixels), so I deleted it. Please reformat your image so that it is about 800 x 600.

Also, include the given information, preferably as text in this window.

Fixed.
 
It looks like you have a mistake right at the beginning. I'm assuming that you are given A and B.

If so, A - I =
$$ \begin{bmatrix} 5 - 1 & 3 \\ 3 & 6 - 1\end{bmatrix} = \begin{bmatrix} 4 & 3 \\ 3 & 5\end{bmatrix}$$
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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