Linear and Angular Velocities of a Point on a Rotating Bicycle Wheel

AI Thread Summary
In the discussion about the linear and angular velocities of a point on a rotating bicycle wheel, it is established that while the wheel rotates about a fixed axis, the angular velocity remains constant. However, the linear velocity changes due to the continuous change in direction of the point on the wheel, indicating that linear velocity is not constant. The distinction between linear and angular acceleration is also clarified, with both being vectors; linear acceleration changes due to the changing direction of velocity. The conversation emphasizes that while angular velocity is constant, linear velocity is variable because of its directional changes. Overall, the key takeaway is that only angular velocity remains constant in this scenario.
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Homework Statement



consider a point on a bicycle wheel as the wheel turns about a fixed axis, neither speeding up nor slowing down. Compare the linear and angular velocities of the point. [The subsequent question asks about the linear and angular accelerations
a. both are constant
b. only the angular velocity is constant
c. only the linear velocity is constant
d. neither is constant

Homework Equations



v=rw

The Attempt at a Solution



im debating between answers a. and b. I would think only the angular velocity is constant. "linear" velocity would change since the direction is always changing (making the velocity vector always changing). I'm not sure though whether linear velocity means a vector or not. Would this be the same for angular/linear acceleration?
 
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Linear acceleration is a vector. You are correct to conclude that changing direction is one way of changing the acceleration. Angular acceleration is also a vector, but the direction of angular acceleration is along the axis of rotation.
 
what about linear velocity?
 
p0ke said:
what about linear velocity?

It's a vector too, of course. Further on, you may think of the angular velocity as a vector, and write \vec{v}=\vec{\omega} \times \vec{r}.
 
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