Linear Dependency: Proving Vector Independence in V

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SUMMARY

In a vector space V with three linearly independent vectors e1, e2, and e3, the vectors e1+e2, e2-e3, and e3+2e1 are also proven to be linearly independent. This is established by analyzing the linear combination c1(e1+e2) + c2(e2-e3) + c3(e3+2e1) = 0, which leads to the rearranged equation (c1+2c3)e1 + (c1+c2)e2 + (c3-c2)e3 = 0. The independence of e1, e2, and e3 implies that the coefficients c1+2c3, c1+c2, and c3-c2 must all equal zero, confirming the linear independence of the new vectors.

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Yankel
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Hello,

I need some help with this one...any guidance will be appreciated.

In a vector space V there are 3 linearly independent vectors e1,e2,e3. Prove that the vectors:

e1+e2 , e2-e3 , e3+2e1

are also linearly independent.

Thanks...
 
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Yankel said:
Hello,

I need some help with this one...any guidance will be appreciated.

In a vector space V there are 3 linearly independent vectors e1,e2,e3. Prove that the vectors:

e1+e2 , e2-e3 , e3+2e1

are also linearly independent.

Thanks...

We want to see when the combination
\[c_1(e_1+e_2)+c_2(e_2-e_3)+c_3(e_3+2e_1)=0\]
Rearranging the terms we get
\[(c_1+2c_3)e_1+(c_1+c_2)e_2+(c_3-c_2)e_3=0\]
Since $e_1,e_2,e_3$ are independent, what does that say about the value of the coefficients $c_1+2c_3, c_1+c_2, c_3-c_2$?

You should have enough information now to finish off this problem.
 

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