Linear Mass Density - Bars (Center of Mass)

AI Thread Summary
The discussion revolves around calculating the center of mass for four black bars with constant linear density. The key equation used is M0 X = summation of (MiXi), where M represents mass. A point of confusion arises regarding the mass distribution, specifically why the mass at the center of the bars is less despite uniform density. It is clarified that the bars along the diagonals have a length of L/√2, leading to a mass of M/√2 for each. This explanation resolves the initial misunderstanding about mass distribution in the configuration.
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1. Homework Statement
The 4 black bars have constant linear density. In terms of L, find the coordinate of the center of mass

Homework Equations


M0 X = summation of (MiXi)

The Attempt at a Solution


I understand most of the solution, except the answer key says one thing I don't get
M/sqrt(2) at (L/4, L/4)
and at (L/4, 3L/4).
Why is there less mass in the middle of bar though the bar is uniform?
 
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M is the mass of a bar of length L. The diagonal of the square is L√2. Half the diagonal is L/√2. That's the length of each of the smaller little bars along the diagonals. So their masses must be M/√2.

Chet
 
Thanks! That made a lot of sense.
 
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