Linear Transformations matrix help

DanielJackins
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Homework Statement



Two questions;

1. Let v1 = [-3, -4] and v2 = [-2, -3]

Let T: R^2 -> R^2 be the linear transformation satisfying T(v1) = [29, -35] and T(v2) = [22, -26]

Find the image of the arbitrary vector [x, y]

T[x,y] = [ _ , _ ]

2. The cross product of two vectors in R^3 is defined by [a1,a2,a3] x [b1,b2,b3] = [a2b3-a3b2, a3b1-a1b3, a1b2-a2b1]

Let v = [2,6,-4]

Find the matrix A of the linear transformation from R^3 to R^3 given by T(x) = v x x.

A = ? (3x3 matrix)

The Attempt at a Solution



For question 1, I found a T[x,y] but it's a 2x2 matrix [{-197, -8/7},{135,8/7}], but maybe I'm understanding the question wrong?

And for question 2, I really have no idea where to start. Wouldn't I need to be provided with a matrix x if were to find T(x) = v x x? Thanks for any help
 
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You are confusing the representation of the transformation as a matrix with its result as an operator. The domain and range of the operator in 1 is R2. I didn't check your calculations in 1, but if the transformation is represented by the matrix you say it is, you should be able to calculate T([x,y]), which should be in R2.

You got the matrix in part 1 by knowing what T did to a couple of points in R2. Do the same thing for part 2.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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