Linear velocity at equator with respect to the sun

AI Thread Summary
The discussion revolves around calculating the linear velocity of a person at the Earth's equator with respect to the Sun when the Sun is on the eastern horizon. It emphasizes that this is a circular motion problem, where the tangential velocity at the equator must be considered in relation to both the Earth and the Sun. The initial approach suggested using the formula v = d/t, but the challenge lies in understanding how to incorporate the "with respect to" aspect and the significance of the eastern horizon. A visual representation is recommended to aid in comprehending the relationship between the Earth and the Sun. Ultimately, the problem requires numerical analysis to determine the relevant velocities accurately.
deathcap00
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Homework Statement



What is the linear velocity of a persion standing at the Earth’s equator with respect to the Sun, when the Sun is just at the Eastern horizon?

Homework Equations



Not sure, I used to v=d/t to solve for a person's linear velocity at the equator, just not sure how to handle the "with respect to" portion and how to use the "eastern horizon" information to help shape a solution.
 
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Do I consider the Earth a particle circling the sun first or something?
 
does anyone have any suggestions on this one? I can't see to figure it out, thanks all.
 
deathcap00 said:

Homework Statement



What is the linear velocity of a persion standing at the Earth’s equator with respect to the Sun, when the Sun is just at the Eastern horizon?

Homework Equations



Not sure, I used to v=d/t to solve for a person's linear velocity at the equator, just not sure how to handle the "with respect to" portion and how to use the "eastern horizon" information to help shape a solution.

Although the problem mentions "linear velocity", this is a circular motion problem. A person standing on the Equator has a tangential velocity relative to the center of the Earth, and it also has a tangential velocity relative to the center of the Sun. It may turn out that the "speed", or magnitude, of one of these tangential velocities is negligible when compared to the other, but you must run the numbers through to see. Step #1, for you, is to draw a picture. I'll get you started:

http://img246.imageshack.us/img246/4949/Earth'sun.jpg

n.b. Picture is not to scale, \rm \frac{R_E}{1 AU} \sim 1~x~10^{-5}
 
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