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Liquid pressure in a closed system

  1. Jan 29, 2014 #1

    klk

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    1. The problem statement, all variables and given/known data
    A steel cylinder filled with water contains 3000psi of pressure, completely sealed, walls ≈ infinite thick. No gas is present inside of the cylinder, and no heat exchange. To the problem; if a solid rod/piston enters on top of the cylinder with no possibilities to bleeding off the pressure, what will the pressure build up be if the rod enters the cylinder with 1 ft?

    Height of cylinder 500ft, ID of cylinder 8,535in, OD of piston 4in, Temperature of water 333,15K→ Isothermal compressibility of water β= 3,0621e-6 [psi-1]


    2. Relevant equations

    β=(1/V)*(∂V/∂P)
    F=P*A


    3. The attempt at a solution
    Volume before entering the the piston V1= 35,4bbl, after V2 = 35,384 bbl
    Solved the above equation for P2 = P1 - ((V2-V1)/(V1*β)). This gave a new pressure inside the cylinder of 4429,9 psi.
    I think this pressure is too high compared to the displaced volume that the piston occupies. I am a bit uncertain if the equation above is correct to use for this situation.

    Please help, thank you.
     
  2. jcsd
  3. Jan 29, 2014 #2
    Hi klk. Welcome to Physics Forums!!!

    I calculate a pressure increase that's a factor of 10 lower than yours.
     
  4. Jan 30, 2014 #3

    klk

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    Thank you for the input, that actually helped me!

    I simply added up the volume it takes to pressure up to 3000psi and the displaced volume from the piston -> dV.

    P2 = dV/(V1*3,2e-6), which gave me a new pressure of 3142 approx..
     
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