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The heat capacity for the liquid is given, the rise in temp. Is given.

According to the first law of thermo, dQ=dW + dU

here dQ is 0.

Asked, is to find the work done on the system, i.e. -dW =dU

The correct solution to this is dU = m*s*dT

My question is , how can this formula be used ?? Since the correct formula is dQ=m*s*dT

??