Lithium Iron Disulfide Battery Chemistry

AI Thread Summary
Research on Lithium Iron Disulfide Batteries highlights the need for clarification on the half-equations for the cathode and anode. The overall reaction is 4Li + FeS(2) → Fe + 2Li(2)S, indicating lithium is oxidized while iron disulfide is reduced. Initial half-equations proposed include lithium oxidation (Li → Li(+) + e-) and a combined reaction for iron disulfide, which was corrected to separate the reactions for clarity. The correct cathode reaction should balance charge, suggesting FeS2 → Fe + S2(2-) with appropriate electron adjustments. This discussion emphasizes the importance of accurately representing half-reactions in battery chemistry.
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I've been researching Lithium Iron Disulfide Batteries, but I've been unable to find the half-equations for the Cathode and Anode.

Cathode - Iron Disulfide
Anode - Lithium
Electrolyte - Organic Solvent Blend (Propylene Carbonite, Dioxolane, Dimethoxyethane)

The overall equation is,

4Li + FeS(2) --> Fe + 2Li(2)S

Any help would be greatly appreciated.

Thanks in advance.
 
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No idea what is exactly happening in these batteries, but just looking at overall equation it is obvious what is getting oxidized and what is getting reduced, so half reactions seem pretty straghtforward.

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Borek said:
so half reactions seem pretty straghtforward.

Not for me, I've not done chemistry since GCSE :S

Anyway, this is what I've come up with,

Li --> Li(+) + e-

and

FeS(2) + 4Li(+) + 4e- -- > Fe + 2Li(2)S

How do they look?

Cheers
 
First one - lithium oxidation - is OK. There is a problem with the other one, as you have mixed both half reactions together. You need something like FeS2 -> Fe + S22-, just balanced with electrons so that charge is identical on both sides.

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Ok, thanks for that.
 
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