Little trees makes angle around turn

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SUMMARY

The discussion focuses on calculating the angle θ that a Little Trees air freshener makes with the vertical when a car turns around a corner of radius R at speed v. The derived formula for θ is arctan(v²/Rg), where g represents gravitational acceleration. The user successfully applied the principles of radial acceleration and tension in their calculations, leading to the conclusion that gravity influences the angle of the air freshener. The discussion emphasizes the relationship between speed, radius, and gravitational force in determining the angle of inclination.

PREREQUISITES
  • Understanding of radial acceleration (v²/R)
  • Basic knowledge of forces and tension in physics
  • Familiarity with trigonometric functions, specifically arctan
  • Concept of gravitational acceleration (g)
NEXT STEPS
  • Study the effects of varying gravitational acceleration on angular displacement
  • Explore the relationship between centripetal force and tension in different scenarios
  • Learn about the implications of angular motion in real-world applications
  • Investigate advanced mechanics topics, such as non-inertial reference frames
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Students learning introductory mechanics, physics enthusiasts, and anyone interested in understanding the dynamics of objects in circular motion.

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Homework Statement


Your car is smelly so you've placed a Little Trees air freshener in your rear view mirror. You begin to turn around a corner of radius R and the little tree starts to make an angle θ from the vertical. What is the angle θ as a function of the speed v and and radius R?


Homework Equations


radial acceleration= v2/R

The Attempt at a Solution


So I began by drawing a triangle with the hypotenuse representing the tension vector, T, at an angle of Θ from the vertical. I represented the opposite side TsinΘ and the adjacent side as TcosΘ. I then calculated the net forces on the little tree...

∑Fy=TcosΘ-mg=0
∑Fx=TsinΘ=ma

I figured that a here represents the radial acceleration, so I let a= v2/R. Because there is no y movement, I ignored y-axis forces.

So I changed the equation to be:
TsinΘ=mv2/R

This is sort of where I ran into trouble. So I can't have T in the equation so I substituted in T=mg/cosΘ from the y equation. When I plug this into the primary equation, I end up having after cancellation:
gtanΘ=v2/R. I further simplified this to give me the desired function:

arctan(v2/Rg)=Θ

I'm not sure if I did it correctly because I have g left in the final equation, and I'm not sure how to get it out.

This is my first post on this website, I am teaching myself intro mechanics over the summer and I found this off of a university's old exam and there is no solutions guide, so any confirmation or correction of my solution would be much appreciated. Thanks!
 
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Well done - why do you need to get rid of the g in the equation - if gravity were stronger, what do you think would happen to the angle the tree hangs for the same centripetal acceleration?
 

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